//连续正整数的和
#include<stdio.h>
int main(){
int n,i=1,j,sum=0;
scanf("%d",&n);
while(i < n/2+1){
sum = i;
for(j=i+1;j<n;j++){
sum += j;
if(sum>=n)
break;
}
if(sum == n)
printf("%d %d\n",i,j);
i++;
}
return 0;
}
原文：https://www.cnblogs.com/Hqx-curiosity/p/12258314.html