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551. Student Attendance Record I

时间:2020-02-05 11:11:05      阅读:50      评论:0      收藏:0      [点我收藏+]

You are given a string representing an attendance record for a student. The record only contains the following three characters:

 

  1. ‘A‘ : Absent.
  2. ‘L‘ : Late.
  3. ‘P‘ : Present.

 

A student could be rewarded if his attendance record doesn‘t contain more than one ‘A‘ (absent) or more than two continuous ‘L‘ (late).

You need to return whether the student could be rewarded according to his attendance record.

Example 1:

Input: "PPALLP"
Output: True

 

Example 2:

Input: "PPALLL"
Output: False

class Solution {
    public boolean checkRecord(String s) {
        int abs = 0;
        int cl = 0;
        for(int i = 0; i < s.length(); i++){
            char c = s.charAt(i);
            if(c == ‘L‘) cl++;
            else if(c == ‘A‘){
                cl = 0;
                abs++;
            }
            else cl = 0;
            if(abs >= 2 || cl >= 3) return false;
        }
        return true;
    }
}

 

551. Student Attendance Record I

原文:https://www.cnblogs.com/wentiliangkaihua/p/12262407.html

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