Python学习笔记——列表需要同时连接整型和字符串时的解决方案

 1 tup = ([‘a‘,‘a1‘],[‘b‘,‘b2‘],[‘c‘,‘c3‘])
 2 ls = [[‘d‘,1,],[‘e‘,2],[‘f‘,3]]
 3 b = []
 4 
 5 #for i in range(2):
 6 #    a = ls[0][i] + ":" + ls[1][i] + ":" + ls[2][i]  #该条指令会报错
 7 #    b.append(a)     
 8 for i in range(2):    
 9     a = tup[0][i] + ":" + tup[1][i] + ":" + tup[2][i]
10     b.append(a)
11     
12 print(b)
13 
14 输出 > [‘a:b:c‘, ‘a1:b2:c3‘]

1 ls = [[‘d‘,1,],[‘e‘,2],[‘f‘,3]]
2 b = []
3 
4 for i in range(2):
5     b[i] = "{}:{}:{}".format(ls[0][i],ls[1][i],ls[2][i])
6 
7 print(b)
8 
9 输出 > [‘d:e:f‘, ‘1:2:3‘]