简单题。注意python的s[:-1]在s == ‘‘时，也是生效的。（返回‘‘）
class Solution:
def backspaceCompare(self, S: str, T: str) -> bool:
normS = self.normalize(S)
normT = self.normalize(T)
return normS == normT
def normalize(self, s: str) -> str:
normStr = ‘‘
for char in s:
if char == ‘#‘:
normStr = normStr[:-1]
else:
normStr += char
return normStr
[leetcode]Backspace String Compare
原文：https://www.cnblogs.com/lautsie/p/12268760.html