用JPEXS反编译flash.swf得到441张黑白图片和1个mp3文件
软件下载地址：https://github.com/jindrapetrik/jpexs-decompiler/releases
右键导出图片
图片很规律，张数刚好是441=21*21，按照图片顺序，黑为1白为0，拼凑出0-1序列
图像处理脚本——识别1和0：
from PIL import Image def aaa(s): image = Image.open("frames/"+str(i)+".png") a,b,c,d = image.getpixel((50,50)) return a s=‘‘ for i in range(1,442): if aaa(i)==0: s+=‘1‘ else: s+=‘0‘ print (s)
输出：
111111100110001111111100000100111001000001101110101011001011101101110100100101011101101110100101101011101100000100110001000001111111101010101111111000000001010100000000111011111011111000100110110011011101111011101101111001101111011010010001100000000011111010100000100011000000000001011100110011111111101011100110101100000101101000100010101110101011011000001101110100101101110000101110101101110110001100000101011100010010111111101101100001011
尝试一下拼一起
图片处理脚本——拼接图片：
from PIL import Image length = 21 img = Image.new(‘RGB‘, (length*5, length*5)) #黑点为1白点为0 data = "111111100110001111111100000100111001000001101110101011001011101101110100100101011101101110100101101011101100000100110001000001111111101010101111111000000001010100000000111011111011111000100110110011011101111011101101111001101111011010010001100000000011111010100000100011000000000001011100110011111111101011100110101100000101101000100010101110101011011000001101110100101101110000101110101101110110001100000101011100010010111111101101100001011" for x in range(length): for y in range(length): if data[x*length+y] == ‘1‘: for xx in range(x*5, x*5+5): for yy in range(y*5, y*5+5): img.putpixel([xx, yy], (0,0,0)) else: for xx in range(x*5, x*5+5): for yy in range(y*5, y*5+5): img.putpixel([xx, yy], (255,255,255)) img.save(‘out.png‘)
输出：
得到前半个flag
*ctf{half_flag_&
再导出mp3文件，这个是常见套路频谱隐写，得到后半段flag
&_the_rest}
原文：https://www.cnblogs.com/wkzb/p/12286505.html