1 public class Solution { 2 public int NumberOf1(int n) { 3 int count = 0; 4 while(n != 0) { 5 count++; 6 n = (n - 1) & n; 7 } 8 9 return count; 10 } 11 }
二进制中1的个数
原文：https://www.cnblogs.com/hyxsolitude/p/12305483.html
