//(ak,bk)=([k*(1+sqrt(5))/2],[k*(1+sqrt(5))/2]+k)=(ak,ak+k)
1 #include <cstdio> 2 double sqrt5=2.2360679774997896964091736687313; 3 int main(){ 4 for(int a,b;scanf("%d%d",&a,&b)!=EOF;puts((((int)((b-a)*(1+sqrt5)/2)))==a?"0":"1")) 5 a>b?a^=b,b^=a,a^=b:0; 6 return 0; 7 }
原文：https://www.cnblogs.com/JasonCow/p/12331329.html