z_c0 = {}
z_c1 = {1:"we", "er":12, (1, 2):(4, 5)}
print(z_c0)
print(z_c1)
z_c2 = {1:3, "we":7}
z_c3 = [1, "ty", (1, 4)]
print(id(z_c2))
print(id(z_c2.fromkeys(z_c3)))
print(z_c2.fromkeys(z_c3)) #创建字典z_c2,以z_c3为key,全部赋值None
print(z_c2.fromkeys(z_c3, 10)) #创建字典z_c2,以z_c3为key,全部赋值10
print(z_c2) #不改变z_c2值
z_f0 = {1:1, "h":"qw", 5:5}
print(z_f0["h"])
z_z0 = {1:"we", 9:0}
z_z0[8] = "tot"
print(z_z0)
z_z1 = {1:1, 2:2, 3:{1,2,3}}
z_z2 = z_z1
z_z3 = z_z1.copy()
z_z1[1] = 89
z_z1[2] = 90
z_z1[3].remove(1)
print(z_z1)
print(z_z2)
print(z_z3)
z_z4 = {1:1, 2:2}
z_z5 = {3:3, 4:("we", "er")}
z_z4.update(z_z5)
print(z_z4)
删除元素
删除字典
清空字典
删除字典给定键key和所对应的值,返回值为被删除的值。key值必须给出。否则,返回预设值
z_s0 = {1:1, 2:2, 3:3}
print(z_s0.pop(1, 10))
print(z_s0)
print(z_s0.pop(5, 10))
print(z_s0)
z_s1 = {1:1, 2:2, 3:3}
print(z_s1.popitem())
print(z_s1)
i in x
以列表形式返回(kye,value)组合
z_x0 = {1:10, 2:20, 3:30}
print(z_x0.items())
print(list(z_x0.items()))
print(z_x0.keys())
print(list(z_x0.keys()))
print(z_x0.values())
print(list(z_x0.values()))
print(z_x0.get(6, None))
print(z_x0.setdefault(1))
print(z_x0.setdefault(10, "阿"))
print(z_x0)原文:https://www.cnblogs.com/TK-tank/p/12345641.html