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python deepcopy的替代方案

时间:2020-02-27 22:14:03      阅读:316      评论:0      收藏:0      [点我收藏+]
from copy import deepcopy
import marshal
import timeit
from multidict import CIMultiDict


def test_deepcopy():
    _kwargs = CIMultiDict({
        "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8",
        "Accept-Encoding": "gzip, deflate, br",
        "Accept-Language": "zh-CN,zh;q=0.9",
        "Host": "www.discogs.com",
        "User-Agent": ("Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_2) "
                       "AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36"),
    })
    if _kwargs is None:
        _kwargs = dict()
    kwargs = deepcopy(_kwargs)


def test_marshal():
    _kwargs = CIMultiDict({
        "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8",
        "Accept-Encoding": "gzip, deflate, br",
        "Accept-Language": "zh-CN,zh;q=0.9",
        "Host": "www.discogs.com",
        "User-Agent": ("Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_2) "
                       "AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36"),
    })
    if _kwargs is None:
        _kwargs = dict()

    kwargs = marshal.loads(marshal.dumps(dict(_kwargs)))


if __name__ == '__main__':
    print(timeit.timeit(stmt=test_deepcopy, number=1000000))
    print("=" * 30)
    print(timeit.timeit(stmt=test_marshal, number=1000000))

测试发现deepcopy是比较耗时的

第一次
21.046875760000002
==============================
6.435647065000001

第二次
19.536858445
==============================
6.0979895100000014

python deepcopy的替代方案

原文:https://www.cnblogs.com/c-x-a/p/12374692.html

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