目录
首先,先贴柳神的博客
想要刷好PTA,强烈推荐柳神的博客,和算法笔记
Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu
first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
. Note: zero (ling
) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai
.
Each input file contains one test case, which gives an integer with no more than 9 digits.
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
-123456789
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
100800
yi Shi Wan ling ba Bai
就是给你一个数字,让你用中国的读法输出出来
① 找到这个九位数字的特点,可以把它4个一分为一节
② 用两个bool类型的量
一个用来判断一节里面有没有零
一个用来判断一节里面有没有已经输出的数
具体的我也不是很懂,这题是抄的算法笔记的
#include<cstdio>
#include<string>
#include<iostream>
#include<cstring>
using namespace std;
char num[10][5] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
char wei[5][5] = { "Shi","Bai","Qian","Wan","Yi" };
int main() {
char str[15];
cin >> str;
int len = strlen(str); //字符串的长度
int left = 0, right = len - 1; //left与right分别指向字符串的首尾元素
if (str[0] == '-') {
printf("Fu"); //如果是负数
left++;
}
while (left + 4 <= right) {
right -= 4; //将right每次左移4位,直到left与right在同一节
}
while (left < len) { //循环每次处理数字的一节(4位或小于4位)
bool flag = false; //flag==flase 表示没有积累的0
bool isPrint = false; //isPrint==false 表示该节没有输出过其中的位
while (left <= right) {
if (left > 0 && str[left] == '0') {
flag = true; //令标记flag为true
}
else {
if (flag == true) {
printf(" ling");
flag = false;
}
//只要不是首位(包括负号),后面的每一位前都要输出空格
if (left > 0)
printf(" ");
printf("%s", num[str[left] - '0']);
isPrint = true; //该节至少有一位被输出
if (left != right) {
printf(" %s", wei[right - left - 1]);
}
}
left++; //left右移1位
}
if (isPrint == true && right != len - 1) {
printf(" %s", wei[(len - 1 - right) / 4 + 2]);
}
right += 4; //right右移4位,输出下一节
}
return 0;
}
PTA甲级1082 Read Number in Chinese (25分)
原文:https://www.cnblogs.com/a-small-Trainee/p/12392695.html