Given a linked list, determine if it has a cycle in it.
To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is no cycle in the linked list.
Example:
Input: head = [3,2,0,-4], pos = 1
Output: true
Explanation: There is a cycle in the linked list, where tail connects to the second node.
Follow up:
Can you solve it using O(1) (i.e. constant) memory?
代码:
public class Solution {
public boolean hasCycle(ListNode head) {
if(head == null || head.next == null) return false;
ListNode fast = head;
ListNode slow = head;
while(fast != null && slow != null){
fast = fast.next;
if(fast != null)
fast = fast.next;
else
return false;
slow = slow.next;
if(fast == slow)
return true;
}
return false;
}
}
注意:
快指针时刻注意空指针错误
LeetCode 141 链表 . Linked List Cycle
原文:https://www.cnblogs.com/muche-moqi/p/12398611.html