CREATE TABLE users(id int(6) NOT NULL AUTO_INCREMENT,PRIMARY KEY (id),user_name VARCHAR(20) NOT NULL,emails VARCHAR(50) NOT NULL);
SELECT * FROM users WHERE emails like "%b@email.com%";
SELECT * FROM users WHERE find_in_set(‘aa@email.com‘, emails);
原文:http://www.cnblogs.com/chen-lhx/p/3951479.html