原题http://acm.hdu.edu.cn/showproblem.php?pid=1873
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4774 Accepted Submission(s): 1976
7 IN 1 1 IN 1 2 OUT 1 OUT 2 IN 2 1 OUT 2 OUT 1 2 IN 1 1 OUT 1
2 EMPTY 3 1 1
//开了三个优先队列。每一个代表一个医生。 #include <stdio.h> #include <stdlib.h> #include <malloc.h> #include <limits.h> #include <ctype.h> #include <string.h> #include <string> #include <queue> #include <stack> #include <deque> #include <set> #include <algorithm> #include <iostream> #include <map> #include <math.h> #include <vector> using namespace std; struct node1{ int sum; int id; friend bool operator < (node1 a,node1 b){ if(a.sum == b.sum){ return a.id > b.id; } return a.sum < b.sum; } }; struct node2{ int sum; int id; friend bool operator < (node2 a,node2 b){ if(a.sum == b.sum){ return a.id > b.id; } return a.sum < b.sum; } }; struct node3{ int sum; int id; friend bool operator < (node3 a,node3 b){ if(a.sum == b.sum){ return a.id > b.id; } return a.sum < b.sum; } }; int main(){ char a[10]; int n,A,B,C; struct node1 p1,p11; struct node2 p2,p22; struct node3 p3,p33; while(~scanf("%d",&n)){ int count = 1; priority_queue<node1>q1; priority_queue<node2>q2; priority_queue<node3>q3; while(n--){ scanf("%s",a); if(a[0] == 'I'){ scanf("%d%d",&A,&B); if(A == 1){ p1.id = count; p1.sum = B; q1.push(p1); } if(A == 2){ p2.id = count; p2.sum = B; q2.push(p2); } if(A == 3){ p3.id = count; p3.sum = B; q3.push(p3); } count++; } else{ scanf("%d",&C); if(C == 1){ if(!q1.empty()){ p11 = q1.top(); q1.pop(); printf("%d\n",p11.id); } else{ printf("EMPTY\n"); } } if(C == 2){ if(!q2.empty()){ p22 = q2.top(); q2.pop(); printf("%d\n",p22.id); } else{ printf("EMPTY\n"); } } if(C == 3){ if(!q3.empty()){ p33 = q3.top(); q3.pop(); printf("%d\n",p33.id); } else{ printf("EMPTY\n"); } } } } } return 0; }
原文:http://blog.csdn.net/zcr_7/article/details/39007499