原题http://acm.hdu.edu.cn/showproblem.php?pid=1873
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4774 Accepted Submission(s): 1976
7 IN 1 1 IN 1 2 OUT 1 OUT 2 IN 2 1 OUT 2 OUT 1 2 IN 1 1 OUT 1
2 EMPTY 3 1 1
//开了三个优先队列。每一个代表一个医生。
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#include <limits.h>
#include <ctype.h>
#include <string.h>
#include <string>
#include <queue>
#include <stack>
#include <deque>
#include <set>
#include <algorithm>
#include <iostream>
#include <map>
#include <math.h>
#include <vector>
using namespace std;
struct node1{
int sum;
int id;
friend bool operator < (node1 a,node1 b){
if(a.sum == b.sum){
return a.id > b.id;
}
return a.sum < b.sum;
}
};
struct node2{
int sum;
int id;
friend bool operator < (node2 a,node2 b){
if(a.sum == b.sum){
return a.id > b.id;
}
return a.sum < b.sum;
}
};
struct node3{
int sum;
int id;
friend bool operator < (node3 a,node3 b){
if(a.sum == b.sum){
return a.id > b.id;
}
return a.sum < b.sum;
}
};
int main(){
char a[10];
int n,A,B,C;
struct node1 p1,p11;
struct node2 p2,p22;
struct node3 p3,p33;
while(~scanf("%d",&n)){
int count = 1;
priority_queue<node1>q1;
priority_queue<node2>q2;
priority_queue<node3>q3;
while(n--){
scanf("%s",a);
if(a[0] == 'I'){
scanf("%d%d",&A,&B);
if(A == 1){
p1.id = count;
p1.sum = B;
q1.push(p1);
}
if(A == 2){
p2.id = count;
p2.sum = B;
q2.push(p2);
}
if(A == 3){
p3.id = count;
p3.sum = B;
q3.push(p3);
}
count++;
}
else{
scanf("%d",&C);
if(C == 1){
if(!q1.empty()){
p11 = q1.top();
q1.pop();
printf("%d\n",p11.id);
}
else{
printf("EMPTY\n");
}
}
if(C == 2){
if(!q2.empty()){
p22 = q2.top();
q2.pop();
printf("%d\n",p22.id);
}
else{
printf("EMPTY\n");
}
}
if(C == 3){
if(!q3.empty()){
p33 = q3.top();
q3.pop();
printf("%d\n",p33.id);
}
else{
printf("EMPTY\n");
}
}
}
}
}
return 0;
}
原文:http://blog.csdn.net/zcr_7/article/details/39007499