将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ListNode returnNode = new ListNode(0); Merge(l1, l2, returnNode); return returnNode.next; } public void Merge(ListNode l1, ListNode l2, ListNode returnNode) { if(l1 == null) { returnNode.next = l2; return; } else if(l2 == null) { returnNode.next = l1; return; } else { if(l1.val <= l2.val) { returnNode.next = l1; ListNode tmpNode = l1.next; ListNode tmpNode1 = returnNode.next; Merge(tmpNode, l2, tmpNode1); } else { returnNode.next = l2; ListNode tmpNode = l2.next; ListNode tmpNode1 = returnNode.next; Merge(l1, tmpNode, tmpNode1); } } } }
今日一句:
时间能治愈一切,请给时间一点时间。
原文:https://www.cnblogs.com/Duancf/p/12458881.html