将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode returnNode = new ListNode(0);
Merge(l1, l2, returnNode);
return returnNode.next;
}
public void Merge(ListNode l1, ListNode l2, ListNode returnNode)
{
if(l1 == null)
{
returnNode.next = l2;
return;
}
else if(l2 == null)
{
returnNode.next = l1;
return;
}
else
{
if(l1.val <= l2.val)
{
returnNode.next = l1;
ListNode tmpNode = l1.next;
ListNode tmpNode1 = returnNode.next;
Merge(tmpNode, l2, tmpNode1);
}
else
{
returnNode.next = l2;
ListNode tmpNode = l2.next;
ListNode tmpNode1 = returnNode.next;
Merge(l1, tmpNode, tmpNode1);
}
}
}
}
今日一句:
时间能治愈一切,请给时间一点时间。
原文:https://www.cnblogs.com/Duancf/p/12458881.html