Given a string s
. You should re-order the string using the following algorithm:
s
and append it to the result.s
which is greater than the last appended character to the result and append it.s
and append it to the result.s
which is smaller than the last appended character to the result and append it.s
.In each step, If the smallest or the largest character appears more than once you can choose any occurrence and append it to the result.
Return the result string after sorting s
with this algorithm.
Example 1:
Input: s = "aaaabbbbcccc" Output: "abccbaabccba" Explanation: After steps 1, 2 and 3 of the first iteration, result = "abc" After steps 4, 5 and 6 of the first iteration, result = "abccba" First iteration is done. Now s = "aabbcc" and we go back to step 1 After steps 1, 2 and 3 of the second iteration, result = "abccbaabc" After steps 4, 5 and 6 of the second iteration, result = "abccbaabccba"
Example 2:
Input: s = "rat" Output: "art" Explanation: The word "rat" becomes "art" after re-ordering it with the mentioned algorithm.
Example 3:
Input: s = "leetcode" Output: "cdelotee"
Example 4:
Input: s = "ggggggg" Output: "ggggggg"
Example 5:
Input: s = "spo" Output: "ops"
class Solution { public String sortString(String s) { int le = s.length(); int[] arr = new int[26]; for(int i = 0; i < le; i++){ arr[s.charAt(i) - ‘a‘]++; } StringBuilder sb = new StringBuilder(); while(le > 0){ for(int i = 0; i < 26; i++){ if(arr[i] > 0){ sb.append((char) (‘a‘ + i)); arr[i]--; le--; } } for(int i = 25; i >= 0; i--){ if(arr[i] > 0){ sb.append((char) (‘a‘ + i)); arr[i]--; le--; } } } return sb.toString(); } }
按题意写。。
1370. Increasing Decreasing String
原文:https://www.cnblogs.com/wentiliangkaihua/p/12460192.html