Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.
The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.
Example 1:
Input: n = 4 Output: "pppz" Explanation: "pppz" is a valid string since the character ‘p‘ occurs three times and the character ‘z‘ occurs once. Note that there are many other valid strings such as "ohhh" and "love".
Example 2:
Input: n = 2 Output: "xy" Explanation: "xy" is a valid string since the characters ‘x‘ and ‘y‘ occur once. Note that there are many other valid strings such as "ag" and "ur".
Example 3:
Input: n = 7 Output: "holasss"
Constraints:
1 <= n <= 500class Solution { public String generateTheString(int n) { StringBuilder sb = new StringBuilder(); if(n % 2 != 0){ for(int i = 0; i < n; i++) sb.append(‘a‘); } else{ for(int i = 0; i < n-1; i++) sb.append(‘a‘); sb.append(‘b‘); } return sb.toString(); } }
又是一道出题人上厕所时出的题
public String generateTheString(int n) { return "b" + "ab".substring(n % 2, 1 + n % 2).repeat(n - 1); }
大佬是这么做的
1374. Generate a String With Characters That Have Odd Counts
原文：https://www.cnblogs.com/wentiliangkaihua/p/12466642.html