Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
水题
逐字符从后往前扫描遇到空格就返回就行了
1 public int lengthOfLastWord(String s) { 2 if(s == null || s.length() ==0){ 3 return 0; 4 } 5 s = s.trim(); 6 byte[] sBytes = s.getBytes(); 7 int j= sBytes.length-1; 8 int total = 0; 9 while(j>=0 && sBytes[j] != 32){ 10 j --; 11 total ++; 12 } 13 return total; 14 }
原文：http://www.cnblogs.com/dijkstra-c/p/3952151.html