每天一习题,提升Python不是问题!!有更简洁的写法请评论告知我!
https://www.cnblogs.com/poloyy/category/1676599.html
如果有一个列表a=[1,3,5,7,11] 问题:1如何让它反转成[11,7,5,3,1] 2.取到奇数位值的数字,如[1,5,11]
直接调用内置函数或切片
切片,设置步长
""" 如果有一个列表a=[1,3,5,7,11] 问题:1如何让它反转成[11,7,5,3,1] """ # 非算法方案一 a = [1, 3, 5, 7, 11] a = a[::-1] print(a) # 非算法方案二 a = [1, 3, 5, 7, 11] a.reverse() print(a) # 算法 a = [1, 3, 5, 7, 11] lens = len(a) for i in range(0, int(lens / 2)): a[i], a[lens - i - 1] = a[lens - i - 1], a[i] print(a) """ 如果有一个列表a=[1,3,5,7,11] 问题:2.取到奇数位值的数字,如[1,5,11] """ a = [1, 3, 5, 7, 11] a = a[::2] print(a)
原文:https://www.cnblogs.com/poloyy/p/12539848.html