热点排名信息获取

import requests
from lxml import etree
#爬取知乎热度的前十名
headers = {‘User-Agent‘:‘Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36 Edge/18.18362‘}
url =  "https://tophub.today/" 
response = requests.get(url,headers = headers) #发送get请求
html = etree.HTML(response.text) #构建一个xpath解析对象
a = html.xpath(".//span[@class=‘t‘]/text()")[50:60] #利用正则表达，爬取知乎排名前十名的标题
b = html.xpath(".//span[@class=‘e‘]/text()")[50:60] #利用正则表达，爬取知乎排名前十名的热度
for i in range(0 , len(a)):
    print("排名:{}--标题:{}------热度:{}".format(i+1,a[i],b[i])) #数据可视化