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Leetcode 217. 存在重复元素 (Contains Duplicate)

时间:2020-03-29 19:03:58      阅读:52      评论:0      收藏:0      [点我收藏+]

题目

Given an array of integers, find if the array contains any duplicates.
Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

Example 1:

Input: [1,2,3,1]
Output: true

Example 2:

Input: [1,2,3,4]
Output: true

Example 3:

Input: [1,1,1,3,3,4,3,2,4,2]
Output: false

Code

class Solution:
    def containsDuplicate(self, nums: List[int]) -> bool:
        d = set()
        for n in nums:
            if n not in d:
                d.add(n)
            else:
                return True
        return False

Leetcode 217. 存在重复元素 (Contains Duplicate)

原文:https://www.cnblogs.com/yufeng97/p/12594021.html

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