Given an array of integers, find if the array contains any duplicates.
Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
Input: [1,2,3,1]
Output: true
Input: [1,2,3,4]
Output: true
Input: [1,1,1,3,3,4,3,2,4,2]
Output: false
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
d = set()
for n in nums:
if n not in d:
d.add(n)
else:
return True
return False
Leetcode 217. 存在重复元素 (Contains Duplicate)
原文:https://www.cnblogs.com/yufeng97/p/12594021.html