C++判断是回文串还是镜像串

#include <iostream>
#include <string>
#include <cstdio>
#include <cctype>
#pragma warning(disable:4996)
using namespace std;
string str = "A   3  HIL JM O   2TUVWXY51SE Z  8 ";//镜像串的特征，只有部分字母和数字有镜像
string out[4] = { "啥都不是","是个回文串","是个镜像串","即是回文串，又是镜像串" };
char r(char s)
{
    if (isalpha(s)) return str[s - ‘A‘];
    return str[s - ‘0‘ + 25];
}
int main() {
    char a[30];
    while (scanf("%s", a) == 1)
    {
        int len = strlen(a);
        int hui = 1, mirror = 1;
        for (int i = 0;i < (len+1) / 2;++i)
        {
            if (a[i] != a[len - i - 1])  hui = 0;//不是回文串
            if (r(a[i]) != a[len - i - 1]) mirror = 0;//不是镜像串
        }
        cout << out[mirror * 2 + hui];
    }
    return 0;
}