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动态规划(3)

时间:2020-04-05 03:20:03      阅读:75      评论:0      收藏:0      [点我收藏+]

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class Solution:
    def maxSubArray(self, nums: List[int]) -> int:

        maxnum = nums[0]
        for i in range(1,len(nums)):
            if nums[i - 1] > 0:
                nums[i] += nums[i - 1]
            maxnum = max(maxnum,nums[i])
        return maxnum
class Solution:
    def maxSubArray(self, nums: List[int]) -> int:
        n = len(nums)
        maxSum = nums[0]
        minSum = sum = 0
        for i in range(n):
            sum += nums[i]
            maxSum = max(maxSum, sum - minSum)
            minSum = min(minSum, sum)
            
        return maxSum

作者:fe-lucifer
链接:https://leetcode-cn.com/problems/lian-xu-zi-shu-zu-de-zui-da-he-lcof/solution/wu-chong-jie-fa-san-chong-yu-yan-java-javascript-p/
来源:力扣(LeetCode)
著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。

 

动态规划(3)

原文:https://www.cnblogs.com/topass123/p/12635139.html

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