题目描述：
统计字符奇偶次数即可
class Solution: def canConstruct(self, s: str, k: int) -> bool: if k > len(s): return False c = collections.Counter(s) o = sum(i % 2 for i in c.values()) return o <= k
leetcode-5326-构造k个回文字符串
原文：https://www.cnblogs.com/oldby/p/12636115.html
