23-5 面试题：1000个员工，我们认为名字和年龄相等，就为同一个人

def __init__(self, name, age, sex, partment):
        self.name = name
        self.age = age
        self.sex = sex
        self.partment = partment

    def __hash__(self):
        return hash(‘%s%s‘ % (self.name, self.sex))

    def __eq__(self, other):
        if self.name == other.name and self.sex == other.sex:
            return True


employ_lst = []   # 得到600个样本
for i in range(200):
    employ_lst.append(Employee(‘alex‘, i, ‘male‘, ‘python‘))   # 这样得到了 年龄不同，名字都为alex的对象们 放入空列表中待用
for i in range(200):
    employ_lst.append(Employee(‘wusir‘, i, ‘male‘, ‘python‘))   # 这样得到了 年龄不同名字都为wusir的对象们 放入空列表中待用
for i in range(200):
    employ_lst.append(Employee(‘taibai‘, i, ‘male‘, ‘python‘))


# print(employ_lst)
employ_set = set(employ_lst)   # set 去重
for person in employ_set:
    print(person.__dict__)    # 查看对象们

# 结果：

# {‘name‘: ‘alex‘, ‘age‘: 0, ‘sex‘: ‘male‘, ‘partment‘: ‘python‘}
# {‘name‘: ‘taibai‘, ‘age‘: 0, ‘sex‘: ‘male‘, ‘partment‘: ‘python‘}
# {‘name‘: ‘wusir‘, ‘age‘: 0, ‘sex‘: ‘male‘, ‘partment‘: ‘python‘}