1.JSON序列化
string JsonStr= JsonConvert.SerializeObject(Entity);
public class RecordResult
{
[JsonProperty("status")]
public int Status { get; set; }
[JsonProperty("error")]
public int Error { get; set; }
}
RecordResult result = new RecordResult();
result.Status = 1;
result.Error = "Error message";
string jsonStr = JsonConvert.SerializeObject(result);
2.JSON反序列化
Class model = JsonConvert.DeserializeObject<Class>(jsonstr);
var result = (RecordResult)JsonConvert.DeserializeObject(jsonstring, typeof(RecordResult)) //或者 var result = JsonConvert.DeserializeObject<RecordResult>(jsonstring)
原文：https://www.cnblogs.com/wfy680/p/12664401.html