1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.
package ssa;
import java.util.Scanner;
public class lianxi {
public static void main(String[] args) {
int[] a = new int[5];
int i, j;
int temp;
Scanner input = new Scanner(System.in);
System.out.println("请输入5个整数:");
for (i = 0; i < 5; i++) {
a[i] = input.nextInt();
}
for (i = 0; i < a.length - 1; i++) {
for (j = 0; j < a.length - 1 - i; j++) {
if (a[j] > a[j + 1]) {
temp = a[j];
a[j] = a[j + 1];
a[j + 1] = temp;
}
}
}
System.out.println("排序后:");
for (i = 0; i < a.length; i++) {
System.out.println(a[i] + "\t");
}
}
}
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found";
package ssa;
import java.util.Scanner;
public class lianxi {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
int[] x={34,22,35,67,45,66,12,33};
System.out.println("请输入一个数:");
int a=input.nextInt();
for(int i=0;i<x.length;i++){
if(x[i]==a){
System.out.println("该数存在于数组中,下标为"+i);
}else{
System.out.println("not found");
}break;
}
}
}
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
package ssa;
import java.util.Scanner;
public class lianxi {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int[][] a = new int[5][4];
int m = 0;
for (int i = 0; i < 5; i++) {
for (int j = 0; j < 4; j++) {
a[i][j] = m;
m++;
}
}
System.out.println("你输入的数组为:");
for (int i = 0; i < 5; i++) {
for (int j = 0; j < 4; j++) {
System.out.print(a[i][j] + "\t");
}
System.out.println();
}
}
}
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
package ssa;
import java.util.Scanner;
public class lianxi {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int[][] a = new int[5][4];
int m = 0;
int max=0;
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 4; j++) {
a[i][j] = m;
m++;
}
}
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length-1; j++) {
if(max<a[i][j]){
max=a[i][j];
}
}
}
System.out.println("最大值是:"+max);
}
}
原文:https://www.cnblogs.com/Libreation/p/12693696.html