1485. 圣杯咒语

class Solution:
    """
    @param Spell: The Spell
    @return: nothing
    """
    ‘‘‘
    大致思路:
    1.生成字典，排序，在逆序，循环判断是否存在j使得j的大写和小写都在dic里面，存在，则直接返回即为最大的值
    ‘‘‘
    def holyGrailspell(self,Spell):
        dic = [i for i in Spell]
        dic = sorted(dic)[::-1]
        for j in dic:
            if j.upper() in dic and  j.lower() in dic:
                return j.upper()