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Python词频统计

时间:2020-05-07 16:35:39      阅读:70      评论:0      收藏:0      [点我收藏+]

 

一、目的

   掌握集合与字典的定义及其操作使用方法;

 

二、内容

  1. 输入一个整数列表L,判断L中是否存在相同的数字:

  (1)若存在,输出YES,否则输出NO;

   代码:

1 L=input(请输入一列整数,并以空格隔开:)
2 lis=L.split( )
3 if len(set(lis))!=len(lis):
4     print(YES)
5 else:
6     print(NO)

   运行结果

     技术分享图片

  (2)若存在,输出YES,同时输出相同的数字;否则输出NO。

    代码:

 1 L=input(请输入一列整数,并以空格隔开:)
 2 lis=L.split( )
 3 if len(set(lis))!=len(lis):
 4     print(YES)
 5     for i in range(len(lis)-1):
 6         for j in range(i+1,len(lis)):
 7             if lis[i]==lis[j]:
 8                 print(lis[i])
 9 else:
10     print(NO)

       运行结果:

    技术分享图片

 2. 从英文字母(区分大小写)和 0~9数字组成的列表中随机生成10个6位数的密码。

  代码:

1 from random import sample
2 s=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u",
3    "v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P",
4    "Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"]
5 for i in range(10):
6     answer = sample(s,6)
7     for j in answer:
8         print(j,end=‘‘)
9     print(\n)

   运行结果:

    技术分享图片

Python词频统计

原文:https://www.cnblogs.com/ynly/p/12843736.html

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