206. 反转链表

class Solution(object):
    def reverseList(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        if not head or not head.next:
            return head
        pre = None
        while head:
            temp = head.next
            head.next = pre
            pre = head
            head = temp
        return pre

206. 反转链表

原文：https://www.cnblogs.com/panweiwei/p/12857205.html