141. 环形链表

方法一思路：

快慢指针。

class Solution(object):
    def hasCycle(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        slow, fast = head, head
        while fast and fast.next:
            slow = slow.next
            fast = fast.next.next
            if fast == slow:
                return True
        return False

方法二思路：

用list或set。

class Solution(object):
    def hasCycle2(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        list = []
        while head:
            if head in list:
                return True
            list.append(head)
            head = head.next
        return False

141. 环形链表

原文：https://www.cnblogs.com/panweiwei/p/12857116.html