题目:
解答:
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 TreeNode* inorderSuccessor(TreeNode* root, TreeNode* p) 13 { 14 if (root == NULL || p == NULL) 15 { 16 return NULL; 17 } 18 if (p->val >= root->val) 19 { 20 return inorderSuccessor(root->right, p); 21 } 22 else 23 { 24 TreeNode* left = inorderSuccessor(root->left, p); 25 return left ? left : root; 26 } 27 } 28 };
面试题 04.06 找出二叉搜索树中指定节点的“下一个”节点
原文:https://www.cnblogs.com/ocpc/p/12861118.html