算法-最大不重复子串Go+python

最大不重复子串是经典的滑动窗口问题

思路:
mp记录每个字符出现的最大索引位置
start记录当前不重复子串的起始索引位置

先用Python实现一遍

def lengthOfLongestSubstring(s: str) -> int:
    if len(s) <= 1: return len(s)
    mp, start, res = {}, 0, 0
    for i, v in enumerate(s):
        if v in mp and mp[v]>=start:
            start = mp[v]+1
        mp[v] = i
        res = max(res, i-start+1)
    return res

完全相同的思路再用Go实现一遍

func lengthOfLongestSubstring(s string) int {
    if len(s) <= 1 {return len(s)}
    mp := make(map[rune]int)
    start, res := 0, 0
    for i, v := range s {
        if _, ok := mp[v]; ok && mp[v] >= start {
            start = mp[v] + 1
        }
        mp[v] = i
        if i-start+1 > res {
            res = i-start+1
        }
    }
    return res
}

leetcode结果如下 (Python总是被碾压, 哭)

算法-最大不重复子串Go+python

原文：https://www.cnblogs.com/chendongblog/p/12918344.html