E - Candies and Two Sisters
题意：给定n,输出满足a+b=n,a>b的个数
解题思路：当n<=2时为0；n>2时，n是偶数为n/2-1,n是奇数为n/2.
ac代码：
#include<iostream>
using namespace std;
int main(){
int t,n;
cin>>t;
while(t--){
cin>>n;
if(n<=2){
cout<<"0"<<endl;
}
else{
if(n%2==0) cout<<n/2-1<<endl;
else cout<<n/2<<endl;
}
}
return 0;
}
原文：https://www.cnblogs.com/nanan/p/12941787.html