class Solution {
public:
    int isPrefixOfWord(string sentence, string searchWord) {
        int len = sentence.length();
        if (sentence[len-1] != ‘ ‘) {
            sentence += " ";
            len++;
        }
        int last = 0;
        vector<string> words;
        for (int i = 1 ; i< len ; i++) {
            if (sentence[i] == ‘ ‘) {
                words.push_back(sentence.substr(last, i-last));
                last = i + 1;
            }
        }
        for (int i = 0 ; i < (int)words.size() ; i++) {
            int lv = words[i].length(), ls = searchWord.length();
            if (lv < ls)    continue;
            if (words[i].substr(0, ls) == searchWord)  return i+1;
        }
        return -1;
    }
};

class Solution {
public:
    int maxVowels(string s, int k) {
        int len = (int)s.length(), cnt = 0, ans = 0;
        for (int i = 0 ; i < k ; i++) {
            if (s[i] == ‘a‘ || s[i] == ‘e‘ || s[i] == ‘i‘ || s[i] == ‘o‘ || s[i] == ‘u‘) {
                cnt++;
            }
        }
        ans = cnt;
        for (int i = k ; i < len ; i++) {
            if (s[i] == ‘a‘ || s[i] == ‘e‘ || s[i] == ‘i‘ || s[i] == ‘o‘ || s[i] == ‘u‘) {
                cnt++;
            }
            if (s[i-k] == ‘a‘ || s[i-k] == ‘e‘ || s[i-k] == ‘i‘ || s[i-k] == ‘o‘ || s[i-k] == ‘u‘) {
                cnt--;
            }
            ans = max(ans, cnt);
        }
        return ans;
    }
};

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    void dfs(TreeNode* root, vector<int>& cnt, int& ans) {
        if (root->left == NULL && root->right == NULL) {
            int sum = 0, odd = 0;
            for (int i = 1 ; i <= 9 ; i++) {
                if (cnt[i] % 2) odd++;
                sum += cnt[i];
            }
            if (sum % 2 == odd)    ans++;
            return;
        }
        if (root->left) {
            cnt[root->left->val]++;
            dfs(root->left, cnt, ans);
            cnt[root->left->val]--;
        }
        if (root->right) {
            cnt[root->right->val]++;
            dfs(root->right, cnt, ans);
            cnt[root->right->val]--;
        }
    }
    int pseudoPalindromicPaths (TreeNode* root) {
        if (root == NULL)   return 0;
        vector<int> cnt = vector<int>(10, 0);
        cnt[root->val]++;
        int ans = 0;
        dfs(root, cnt, ans);
        cnt[root->val]--;
        return ans;
    }
};

class Solution {
public:
    int maxDotProduct(vector<int>& nums1, vector<int>& nums2) {
        int n1 = (int)nums1.size(), n2 = (int)nums2.size(), len = min(n1, n2);
        vector<vector<int>> dp = vector<vector<int>>(n1+1, vector<int>(n2+1, -50000000));
        int ans = INT_MIN;
        for (int i = 0 ; i <= n1 ; i++) {
            dp[i][0] = 0;
        }
        for (int i = 0 ; i <= n2 ; i++) {
            dp[0][i] = 0;
        }
        for (int j = 1 ; j <= n1 ; j++) {
            for (int k = 1 ; k <= n2 ; k++) {
                if (j > 1 && k > 1) {
                    dp[j][k] = dp[j-1][k-1]; 
                }
                if (j > 1) {
                    dp[j][k] = max(dp[j][k], dp[j-1][k]);
                }
                if (k > 1) {
                    dp[j][k] = max(dp[j][k], dp[j][k-1]);
                }
                dp[j][k] = max(dp[j][k], max(dp[j-1][k-1] + nums1[j-1] * nums2[k-1], nums1[j-1] * nums2[k-1]));
                // cout << j << "<>" << k << "==" << dp[j][k] << " | " << ans << endl;
                ans = max(ans, dp[j][k]);
            } 
        }
        return ans;
    }
};