We write the integers of A
and B
(in the order they are given) on two separate horizontal lines.
Now, we may draw connecting lines: a straight line connecting two numbers A[i]
and B[j]
such that:
A[i] == B[j]
;Note that a connecting lines cannot intersect even at the endpoints: each number can only belong to one connecting line.
Return the maximum number of connecting lines we can draw in this way.
Example 1:
Input: A = [1,4,2], B = [1,2,4]
Output: 2
Explanation: We can draw 2 uncrossed lines as in the diagram.
We cannot draw 3 uncrossed lines, because the line from A[1]=4 to B[2]=4 will intersect the line from A[2]=2 to B[1]=2.
Example 2:
Input: A = [2,5,1,2,5], B = [10,5,2,1,5,2]
Output: 3
Example 3:
Input: A = [1,3,7,1,7,5], B = [1,9,2,5,1]
Output: 2
Note:
1 <= A.length <= 500
1 <= B.length <= 500
1 <= A[i], B[i] <= 2000
class Solution { public int maxUncrossedLines(int[] A, int[] B) { int m = A.length, n = B.length, dp[][] = new int[m + 1][n + 1]; for (int i = 1; i <= m; ++i) for (int j = 1; j <= n; ++j) if (A[i - 1] == B[j - 1]) dp[i][j] = 1 + dp[i - 1][j - 1]; else dp[i][j] = Math.max(dp[i][j - 1], dp[i - 1][j]); return dp[m][n]; } }
Longest subsequence
原文:https://www.cnblogs.com/wentiliangkaihua/p/12963054.html