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十进制转换

时间:2020-06-02 14:52:53      阅读:36      评论:0      收藏:0      [点我收藏+]
# bin2dec
# 二进制 to 十进e5a48de588b662616964757a686964616f31333335336437制: int(str,n=10) 
def bin2dec(string_num):
    return str(int(string_num, 2))
 
# hex2dec
# 十六进制 to 十进制
def hex2dec(string_num):
    return str(int(string_num.upper(), 16))
 
# dec2bin
# 十进制 to 二进制: bin() 
def dec2bin(string_num):
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num,rem = divmod(num, 2)
        mid.append(base[rem])
 
    return ‘‘.join([str(x) for x in mid[::-1]])
 
# dec2hex
# 十进制 to 八进制: oct() 
# 十进制 to 十六进制: hex() 
def dec2hex(string_num):
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num,rem = divmod(num, 16)
        mid.append(base[rem])
 
    return ‘‘.join([str(x) for x in mid[::-1]])

base = [str(x) for x in range(10)] + [chr(x) for x in range(ord(A), ord(A) + 6)]

def dec2bin(string_num):
    ‘‘‘十进制转换为 二进制‘‘‘
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 2)
        mid.append(base[rem])

    return ‘‘.join([str(x) for x in mid[::-1]])

def dec2oct(string_num):
    ‘‘‘转换为 八进制‘‘‘
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 8)
        mid.append(base[rem])

    return ‘‘.join([str(x) for x in mid[::-1]])


def dec2hex(string_num):
    ‘‘‘转换为 十六进制‘‘‘
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 16)
        mid.append(base[rem])

    return ‘‘.join([str(x) for x in mid[::-1]])



num = float(input())

print(dec2bin(num),dec2oct(num),dec2hex(num))

2020-06-02

十进制转换

原文:https://www.cnblogs.com/hany-postq473111315/p/13030835.html

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