最大利润

import java.util.Comparator;
import java.util.PriorityQueue;

/**
 * 输入正数数组cost表示每个项目的花费,正数数组profits表示每个项目的利润，M表示初始资金，K表示最多只能串行做k个项目
 * 返回最后获得的最大钱数
 */
public class IPO {

    public static int findMaximizedCapital(int k, int m, int[] profits, int[] costs) {
        PriorityQueue<Program> minCostQ = new PriorityQueue<>(Comparator.comparingInt(a -> a.cost));
        PriorityQueue<Program> maxProfitQ = new PriorityQueue<>((a, b) -> b.profit - a.profit);
        for (int i = 0; i < profits.length; i++) {
            minCostQ.add(new Program(profits[i], costs[i]));
        }
        for (int i = 0; i < k; i++) {
            while (!minCostQ.isEmpty() && minCostQ.peek().cost <= m) {
                maxProfitQ.add(minCostQ.poll());
            }
            if (maxProfitQ.isEmpty()) {
                return m;
            }
            m += maxProfitQ.poll().profit;
        }
        return m;
    }

    public static class Program {

        // 纯利润
        public int profit;

        // 花费
        public int cost;

        public Program(int profit, int cost) {
            this.profit = profit;
            this.cost = cost;
        }

    }

}

/* 如有意见或建议，欢迎评论区留言；如发现代码有误，欢迎批评指正 */

最大利润

原文：https://www.cnblogs.com/laydown/p/13060977.html