罗马数字转整型

# 将罗马数字转换成整型
# class Solution:
#     def romanToInt(self, s):
#         d = {‘I‘: 1, ‘V‘: 5, ‘X‘: 10, ‘L‘: 50, ‘C‘: 100, ‘D‘: 500, ‘M‘: 1000}
#         num = 0
#         for i in range(len(s) - 1):
#             num1 = d[s[i]]
#             num2 = d[s[i+1]]
#             if num1 >= num2:
#                 num += num1
#             else:
#                 num -= num1
#         num += d[s[-1]]
#         return num
#
#
# print(Solution().romanToInt(‘VI‘))

罗马数字转整型

原文：https://www.cnblogs.com/wlj-axia/p/13072123.html