>>> c = arange(20).reshape(5,4)
>>> c
array([[ 0, 1, 2, 3],
[ 4, 5, 6, 7],
[ 8, 9, 10, 11],
[12, 13, 14, 15],
[16, 17, 18, 19]])
c.shape[0]
5
Gives the number of rows
c.shape[1]
4
Gives number of columns
def naive_vector_dot(x, y):
assert len(x.shape) == 1
assert len(y.shape) == 1
assert x.shape[0] == y.shape[0]
z = 0.
for i in range(x.shape[0]):
z += x[i] * y[i]
return z
高维度计算
(a, b, c, d) . (d,) -> (a, b, c)
(a, b, c, d) . (d, e) -> (a, b, c, e)