package com.hxh;
public class Hungry {
private static final Hungry HUNGRY = new Hungry();
private Hungry() {
System.out.println("创建");
}
public static Hungry getInstance() {
return HUNGRY;
}
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
new Thread(() -> {
System.out.println(Hungry.getInstance());
}).start();
}
}
}
注意事项:
- 变量HUNGRY必须是:私有,静态,不可变;
- 构造器私有;
- 公开的
getInstance
方法,使外界可以获取变量。
package com.hxh;
public class LazyMan {
private static LazyMan lazyMan;
private LazyMan() {
System.out.println("LazyMan被创建");
}
public static LazyMan getInstance() {
if (lazyMan == null) {
lazyMan = new LazyMan();
}
return lazyMan;
}
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
System.out.println(LazyMan.getInstance());
}
}
}
输出如下,单线程下看起来毫无问题:
LazyMan被创建
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
com.hxh.LazyMan@39a054a5
修改main函数,改为多线程
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
new Thread(() -> {
System.out.println(LazyMan.getInstance());
}).start();
}
}
从上图可以看出,一共创建了4个对象,并不是单例的。
通过修改获取实例方法getInstance
,给对象加锁解决上面的问题:
public static LazyMan getInstance() {
if (lazyMan == null) {
synchronized (LazyMan.class) {
if (lazyMan == null) {
lazyMan = new LazyMan();
}
}
}
return lazyMan;
}
输出如下:
LazyMan被创建
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
com.hxh.LazyMan@33ca79ec
现在看起来好像并没有什么问题。但是lazyMan = new LazyMan();
这并不是一个原子性操作,极端情况下可能会发生指令重排,那么什么是指令重排呢?
指令重排:
- JVM创建对象分为三步:
- 分配内存空间
- 执行构造方法、创建实例
- 将内存与实例关联
- 问题就出现在上面的步骤中,我们所预期的步骤是123,而编译器有时为了优化性能,会选择其他的顺序执行上面的步骤。在单线程下没有影响,而多线程时就会出现问题,如:
- 线程a执行步骤为132;
- 线程b执行步骤为123;
- 在线程a执行到3时,b线程开始执行,发现对象不为空之后就开始执行下面的语句,可能就会出现异常,因为a线程还未将对象初始化成功。
解决办法也很简单,为lazyMan
对象添加volatitle
关键字,保证不会出现指令重排
完整代码如下:
package com.hxh;
public class LazyMan {
private volatile static LazyMan lazyMan;
private LazyMan() {
System.out.println("LazyMan被创建");
}
public static LazyMan getInstance() {
if (lazyMan == null) {
synchronized (LazyMan.class) {
if (lazyMan == null) {
lazyMan = new LazyMan();
}
}
}
return lazyMan;
}
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
new Thread(() -> {
System.out.println(LazyMan.getInstance());
}).start();
}
}
}
原文:https://www.cnblogs.com/shimeath/p/13159328.html