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c++11 实现numpy argmax argmin

时间:2020-07-20 19:37:14      阅读:103      评论:0      收藏:0      [点我收藏+]

 

#include <algorithm>
#include <vector>
#include <iostream>
#include <array>
using namespace std;
template<class ForwardIterator>
inline size_t argmin(ForwardIterator first, ForwardIterator last)
{
    return std::distance(first, std::min_element(first, last));
}

template<class ForwardIterator>
inline size_t argmax(ForwardIterator first, ForwardIterator last)
{
    return std::distance(first, std::max_element(first, last));
}


int main() {
    array<int, 7> numbers{ 2, 4, 8, 0, 6, -1, 3 };
    size_t minIndex = argmin(numbers.begin(), numbers.end());
    cout << minIndex << \n;
    vector<float> prices = { 12.5f, 8.9f, 100.0f, 24.5f, 30.0f };
    size_t maxIndex = argmax(prices.begin(), prices.end());
    cout << maxIndex << \n;
    return 0;
}

运行结果:

5
2

即返回的索引值分别为5,2.

参考:https://blog.csdn.net/theonegis/article/details/83036074

c++11 实现numpy argmax argmin

原文:https://www.cnblogs.com/juluwangshier/p/13346415.html

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