total合计小于0,必然不能循环
当某个节点的sum小于0时,说明以m开始循环会出现油不够的情况,则进行下一次循环。
public static void main(String[] args) { int[] gas = {2, 3, 1}; int[] cost = {3, 1, 2}; System.out.println(canCompleteCircuit3(gas, cost)); } /** * @param gas=[2,3,1] * @param cost=[3,1,2] * @returnss */ public static int canCompleteCircuit3(int[] gas, int[] cost) { int sum = 0; int total = 0; int start = 0; for (int m = 0; m < gas.length; m++) { total += gas[m] - cost[m]; sum += gas[m] - cost[m]; if (sum < 0) { start=m+1; sum = 0; } } return total < 0 ? -1 : start; }
算法参考:https://www.cnblogs.com/grandyang/p/4266812.html
https://www.cnblogs.com/MrSaver/p/9644679.html
原文:https://www.cnblogs.com/use-D/p/13384365.html