[CF从零单排#18]131A - cAPS lOCK

题目来源：http://codeforces.com/problemset/problem/131/A

wHAT DO WE NEED cAPS LOCK FOR?

Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.

Let‘s consider that a word has been typed with the Caps lock key accidentally switched on, if:

either it only contains uppercase letters;
or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.

Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.

Input
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word‘s length is from 1 to 100 characters, inclusive.

Output
Print the result of the given word‘s processing.

Examples
input
cAPS
output
Caps
input
Lock
output
Lock

题目大意：

给定一个字符串，如果这个字符串全部都是大写字母，那么将它修改成小写字母。如果这个字符串第一个字母是小写，后面全部是大写，那么把第一个字母改成大写，后面改成小写。

题目分析：

模拟题，直接模拟题目意思即可。

参考代码：

#include <bits/stdc++.h>
using namespace std;
int main(){
	char s[110];
	cin >> s;
	int len = strlen(s);
	int count = 0;
	for(int i=0; i<len; i++)
		if(s[i]>=‘A‘ && s[i]<=‘Z‘)
			count ++;
	if(s[0]>=‘a‘ && s[0]<=‘z‘ && count==len-1){
		s[0] += ‘A‘-‘a‘;
		for(int i=1; i<len; i++)
			s[i] += ‘a‘-‘A‘;
	}
	if(count==len){
		for(int i=0; i<len; i++)
			s[i] += ‘a‘-‘A‘;
	}
	for(int i=0; i<len; i++)
		cout << s[i];
	return 0;
} 

[CF从零单排#18]131A - cAPS lOCK

原文：https://www.cnblogs.com/gdgzliu/p/13387353.html