记负均正(HJ97)

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    int n = 0;

    while (cin >> n)
    {
        int count = 0;
        int negativeCount=0;
        double sum = 0;
        int num = 0;

        for (int i = 0; i < n; i++)
        {
            cin >> num;
            if (num < 0)
            {
                count++;
            }
            else if(num>0)
            {
                negativeCount++;
                sum += num;
            }
        }

        cout << count << " "  <<fixed << setprecision(1)<<(1.0*sum / negativeCount) << endl;
    }

    return 0;
}