大数据第28天-MySQL练习题1-杨大伟

1 Create table Person (PersonId int, FirstName varchar(255), LastName varchar(255));
2 
3 Create table Address (AddressId int, PersonId int, City varchar(255), State varchar(255));
4 
5 insert into Person (PersonId, LastName, FirstName) values (1, ‘Wang‘, ‘Allen‘);
6 insert into Address (AddressId, PersonId, City, State) values (1, 1, ‘New York City‘, ‘New York‘);

 1 select
 2      p.FirstName,
 3      p.LastName,
 4      a.City,
 5      a.State
 6 from 
 7      Person as p 
 8 left join 
 9      Address as a 
10 on 
11      p.PersonId = a.PersonId;