首页 > 编程语言 > 详细

python炸鸡

时间:2020-08-15 15:26:01      阅读:73      评论:0      收藏:0      [点我收藏+]

itertools.product()函数

  itertools.product()函数生成列表或类列表值(如 字符串或者元组)里的每项的每种可能组合。

    返回itertools.product对象值,需要把这个值传给列表

    这种组合又名笛卡尔乘积。

exampl1:(3^4 = 81种组合)

>>> itertools.product(ABC, repeat=4)  
<itertools.product object at 0x011F8CC8>
>>> list(itertools.product(ABC, repeat=4)) 
[(A, A, A, A), (A, A, A, B), (A, A, A, C), (A, A, B, A), (A, A, B, B), (A, A, B, C), (A, A, C, A), (A, A, C, B), (A, A, C, C), (A, B, A, A), (A, B, A, 
B), (A, B, A, C), (A, B, B, A), (A, B, B, B), (A, B, B, C), (A, B, C, A), (A, B, C, B), (A, B, C, C), (A, C, A, A), (A, C, A, B), (A, C, A, C), (A, C, 
B, A), (A, C, B, B), (A, C, B, C), (A, C, C, A), (A, C, C, B), (A, C, C, C), (B, A, A, A), (B, A, A, B), (B, A, A, C), (B, A, B, A), (B, A, B, B), (B, 
A, B, C), (B, A, C, A), (B, A, C, B), (B, A, C, C), (B, B, A, A), (B, B, A, B), (B, B, A, C), (B, B, B, A), (B, B, B, B), (B, B, B, C), (B, B, C, A), (B, B, C, B), (B, B, C, C), (B, C, A, A), (B, C, A, B), (B, C, A, C), (B, C, B, A), (B, C, B, B), (B, C, B, C), (B, C, C, A), (B, C, C, B), (B, C, C, C), (C, A, A, A), (C, A, A, B), (C, A, A, C), (C, A, B, A), (C, A, B, B), (C, A, B, C), (C, A, C, A), (C, A, C, B), (C, A, C, C), (C, B, A, A), (C, B, A, B), (C, B, A, C), (C, B, B, A), (C, B, B, B), (C, B, B, C), (C, B, C, A), (C, B, C, B), (C, B, C, C), (C, C, A, A), (C, C, A, B), (C, C, A, C), (C, C, B, A), (C, C, B, B), (C, C, B, C), (C, C, C, A), (C, C, C, B), (C, C, C, C)]
>>> import pprint

example2:(8^5 = 32768)

>>> mylist = list(itertools.product(range(8), repeat=5))
>>> len(mylist) 
32768
>>>

注意遍历次序:

>>> list(itertools.product(range(3), repeat=3)) 
[(0, 0, 0), (0, 0, 1), (0, 0, 2), (0, 1, 0), (0, 1, 1), (0, 1, 2), (0, 2, 0), (0, 2, 1), (0, 2, 2), (1, 0, 0), (1, 0, 1), (1, 0, 2), (1, 1, 0), (1, 1, 1), (1, 1, 2), (1, 2, 0), (1, 2, 1), (1, 2, 2), (2, 0, 0), (2, 0, 1), (2, 0, 2), (2, 1, 0), (2, 1, 1), (2, 1, 2), (2, 2, 0), (2, 2, 1), (2, 2, 2)]
>>>

 

python炸鸡

原文:https://www.cnblogs.com/PiaYie/p/13508694.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!