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PAT 甲级 1117 Eddington Number (25分)

时间:2020-08-30 21:20:58      阅读:60      评论:0      收藏:0      [点我收藏+]
 
British astronomer Eddington liked to ride a bike. It is said that in order to show off his skill, he has even defined an "Eddington number", E -- that is, the maximum integer E such that it is for E days that one rides more than E miles. Eddington‘s own E was 87.

Now given everyday‘s distances that one rides for N days, you are supposed to find the corresponding E (≤ N).

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤), the days of continuous riding. Then N non-negative integers are given in the next line, being the riding distances of everyday.

Output Specification:

For each case, print in a line the Eddington number for these N days.

Sample Input:

10
6 7 6 9 3 10 8 2 7 8

Sample Output:

6    

 

【不知道这题想干啥,让我一度怀疑自己中文水平都有问题】

【理解题意之后,2分钟就写完了,然而最后一个测试点WA]

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 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int n, cnt = 0; cin >> n;
 7     for(int i = 1; i <= n; i++)
 8     {
 9         int x; cin >> x;
10         if(x > i) cnt++;
11     } 
12     cout << cnt;
13     return 0;
14 }
View Code

 

 

PAT 甲级 1117 Eddington Number (25分)

原文:https://www.cnblogs.com/kamisamalz/p/13586419.html

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