思路:定义快慢两个指针,快指针走k步后慢指针开始走,当快指针走到链表尾时快慢指针距离相隔k,倒数第K个结点就是慢指针所指的结点
# -*- coding:utf-8 -*- # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def FindKthToTail(self, head, k): # write code here fast, slow = head, head for i in range(k): if not fast: return fast = fast.next while fast: fast = fast.next slow = slow.next return slow
原文:https://www.cnblogs.com/HHMLXL/p/13606230.html