Given a string S and a string T, count the number of distinct subsequences of T in S.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE"
is
a subsequence of "ABCDE"
while "AEC"
is
not).
Here is an example:
S = "rabbbit"
, T = "rabbit"
Return 3
.
int numDistinct(string S, string T) { vector<vector<int> > dp(S.size() + 1, vector<int>(T.size() + 1, 0)); for(int i = 0; i <= S.size(); ++i) dp[i][0] = 1; for(int i = 1; i <= S.size(); ++i){ for(int j = 1; j <= T.size(); ++j){ if(S[i - 1] == T[j - 1]) dp[i][j] = dp[i - 1][j - 1] + dp[i - 1][j]; else dp[i][j] = dp[i - 1][j]; } } return dp[S.size()][T.size()]; }
Leetcode dp Distinct Subsequences
原文:http://blog.csdn.net/zhengsenlie/article/details/39323571