package LeetCode_509 /** * 509. Fibonacci Number * https://leetcode.com/problems/fibonacci-number/ * * The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, * such that each number is the sum of the two preceding ones, starting from 0 and 1. That is, F(0) = 0, F(1) = 1 F(N) = F(N - 1) + F(N - 2), for N > 1. Given N, calculate F(N). Example 1: Input: 2 Output: 1 Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1. * */ class Solution { /* * solution: DP, Bottom-Up, * Time:O(n), Space:O(n) * */ fun fib(N: Int): Int { if (N == 0) { return 0 } if (N == 1) { return 1 } val dp = IntArray(N + 1) dp[0] = 0 dp[1] = 1 for (i in 2..N) { dp[i] = dp[i - 1] + dp[i - 2] } return dp[N] } }
原文:https://www.cnblogs.com/johnnyzhao/p/13812513.html